Aether CosmologyAether Cosmology · Man of Stone
Brought to you by Man of Stone

A Quick Couple O' Thoughts
About Sunsets

Empirical · Replicable · Aether Cosmology
Sources & channels

Man of Stone

Where to find Man of Stone:
Bitchute — ManOfStone
Telegram — Stone Cold Truth · t.me/+0AvQtagK08Q3ZTU8
Telegram — Stone's Very Own · t.me/+NOcH_v9-11FkMGUx
X / Twitterx.com/Inventionaire
Aether Cosmology
The two statements

Only one can be true.

H₁
The globe

The Sun appears to revolve around a spherical Earth (or vice versa) and is eclipsed below a geometric horizon at sunset.

H₀
Null hypothesis · flat

The Sun appears to recede and fade above a flat Earth into an apparent horizon.

ONLY ONE CAN BE TRUE.

Each hypothesis carries a mutually exclusive geometric outcome for the behavior of shadows at sunset.
These real-world geometric consequences can be tested.

The setup

Two Sun models, one window

H₁ Globe
Globe model
93,000,000 mi away · near-parallel rays · drops straight down.
H₀ Flat
Flat model
Local Sun · diverging rays · recedes & fades.
Method · experimental design

Control, independent & dependent

Each model forces an opposing, observable shadow behavior. H₁ (globe): the Sun drops below the geometric horizon, so the projected shadow must climb above the object casting it and a terminator shadow must overtake the wall. H₀ (flat Earth): the Sun recedes, so the projection slows, stops short, and fades. The next two slides show both outcomes in the Shadow Reveal simulation; below are what varies, what we measure, and what stays fixed.

Control

The vertex

  • the window's bottom edge, the fixed limit by which all light rays pass
  • the vertex altitude is carried across the room to the 30 mm magnet
Independent variable

Distance to the projecting surface

  • window vertex → wall: 6,735 mm
  • distance to the ridge obstruction: 1,396 m
Dependent variable

The inversion, or lack thereof, created by the sunset

  • inverts: the shadow climbs above the vertex line (H₁)
  • never inverts: the climb slows, stops 117 mm short, and fades (H₀)
H₁ · the globe predicts

Projected shadow rises above the object casting it, terminator overtakes it

AAstart
BBclimbing the wall
CCabove the window
DDterminator shadow overtakes · crisp
H₀ · the flat Earth predicts

Projection rises, slows, stops short, fades

AAstart
BBclimbing
CCslows · below the window
DDstops short · fades out
The method · an absolute reference

A magnet fixes the vertex

Facing North: sill altitude carried across to the magnet on the opposite wall
Vertex = the sill
the fixed pivot the shadow turns about
30 mm magnet
stuck on the opposite wall at the same altitude, carried straight across the room
Absolute
it sets the reference and the scale. The sill's height off the floor never enters the math — run it on any floor of a skyscraper.
The decisive test

Only H₁ causes a shadow above the vertex

H₁ Globe - inverts Sill Level Vertex Sun moves BELOW Sill→shadow ABOVE the Sill (Not to scale) Sun moves below Sill→light is cast upward through the vertex→the shadow climbs above the Sill.
H₀ Flat - never inverts Sill Level Vertex Sun recedes ABOVE Sill→shadow stops BELOW Sill (Not to scale) Sun stays above Sill→light is cast downward through the vertex→the shadow stops short, 117mm below the Sill.
Page 5 · the real geometry

This is the room

Room plan, 6735mm to the wall
6,735 mm
door (vertex) → opposite wall
910 × 2060
the door (mm) — the sunset window
2000 × 1500
north window (mm) — ambient light only
Page 5 · handed to the globe

A ridge 16 m higher than the window

Google Earth ridge
1,396 m
to the ridge · heading 252°
16 m
ridge above the window (212 m → 228 m)
170 m
valley low point — land plays no part
Recording one

November 2024

The lit window-shape climbs the wall over ~20 minutes, then levels off as the disc fades.

November graph
November fade-out
Recording two · the clear-cut measurement

February 2025 — the departure

Inverted to match the Sun's actual downward motion: the measured rate departs from the constant-rate line in the final minutes; it slows, stops, and the disc fades. In geometric terms, on a globe, the downward component of the Sun's apparent movement rate increases toward its maximum at one's zenith minus 90 degrees.

February data inverted on the Y axis with zoom box showing the departure
Page 8 · 117 mm · 0.34° · 70%

The measurement

Fade-out with zoomed 117mm measurement
117 mm
shortfall below the sill / magnet
0.995° & 0.655°
red = top-of-Sun ray → 24.3 m above the sill line at the ridge · green = ridge crest → 16 m
0.34° ≈ 70%
the 8.3 m gap at 1,396 m — 70% of the Sun's 0.53° disc still above the ridge
Angular summary bar
Page 9 · the geometric truth

70% of the Sun, still above the ridge

Sun 70% above the ridge

"We can still see 70% of the Sun as it fades out above the horizon. That is the geometric truth."

Setting while on a globe, the Sun cannot still be 70% above the alleged geometric horizon. It descends at 15°/hour and is eclipsed in production of a terminator shadow (the Earth-curve).

But we do not experience that shadow.

Refraction only slightly delays when it appears to set; it does not cause the rate of climb to slow, stop and then fade.

Both observations · Nov + Feb

The verdict

Negated
H₁ — the globe

The Sun appears to revolve around a spherical Earth and eclipse below a geometric horizon. Not supported by the data.

Affirmed
H₀ — flat

The Sun recedes and fades above a flat Earth into an apparent horizon. Supported by the data.

The wall is the instrument: the shadow died 117 mm below the magnet, marking the top of the Sun at 0.995° above the vertex. That same angle passes the ridge 24.3 m above the Sill line, clearing the 16 m peak (which should obstruct it) by 8.3 m. That is 0.34° above the ridge: ~70% of the solar disc still visible above the local point of occlusion as the Sun fades out. The globe model requires the shadow to rise above the vertex. It never does because the Sun doesn't go down; it goes away.

Game over, gang.
The Earth measures flat with respect to sunsets;
affirmed through shadow geometry.
Amendment · show the work

The trigonometry

Every number in this deck comes from two right triangles sharing one vertex. Here is the full work: the equations, the inputs, the results.

01
The wall angle · measured in the room
θwall = arctan( 117 mm / 6,735 mm )
     = arctan( 0.01737 ) = 0.995°
inputs: 117 mm shadow shortfall below the magnet · 6,735 mm room depth, window vertex → wall
02
The ridge angle · from the topography
θridge = arctan( 16 m / 1,396 m )
     = arctan( 0.01143 ) = 0.655°
inputs: ridge 228 m − house 212 m = 16 m · 1,396 m @ 252° (Google Earth)
03
The ray at the ridge plane · one straight line
Hray = 1,396 m × tan( 0.995° ) = 24.3 m
ΔH = 24.3 m − 16 m = 8.3 m
the top-of-Sun ray, carried out the door to the ridge's distance
04
The visible disc · how much Sun is left
Δθ = 0.995°0.655° = 0.340°
Δθ / δSun = 0.34° / 0.50° = 68%~70%
δSun0.5° (30 arcmin) · vertical compression near the horizon lifts 68% past 70%
One straight line through the vertex: 117 / 6,735 = 0.01737 = 24.3 / 1,396. The wall measures the sky.

Slides

jump to any section
← → arrows · L for slides · F fullscreen